awk -F, '$6==10' | awk | available shells /etc/shells
Show rows in the CSV file which column =6 have value = 10
gzcat filename.csv.gz | awk -F, '$6==10'------------------------------------------------
The following program searches the system password file and prints the entries for users whose full name is not indicated:
awk -F: '$5 == ""' /etc/passwd
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awk -F: '{print $4}'
awk
- this is the interpreter for the AWK Programming Language. The AWK language is useful for manipulation of data files, text retrieval and processing-F <value>
- tellsawk
what field separator to use. In your case,-F:
means that the separator is:
(colon).'{print $4}'
means print the fourth field (the fields being separated by:
).
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cat ds | awk '{print$1,$2}'
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type cat /etc/shells to see a list of available shells
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